3
drop table if exists t1;
6
select (1,2,3) IN ((3,2,3), (1,2,3), (1,3,3));
7
select row(10,2,3) IN (row(3,2,3), row(1,2,3), row(1,3,3));
8
select row(1,2,3) IN (row(3,NULL,3), row(1,2,3), row(1,3,3));
9
select row(10,2,3) IN (row(3,NULL,3), row(1,2,3), row(1,3,3));
11
select row('a',1.5,3) IN (row(1,2,3), row('a',1.5,3), row('a','a','a'));
12
select row('a',0,3) IN (row(3,2,3), row('a','a','3'), row(1,3,3));
14
select row('a',0,3) IN (row(3,2,3), row('a','0','3'), row(1,3,3));
15
select row('a',1.5,3) IN (row(3,NULL,3), row('a',1.5,3), row(1,3,3));
16
select row('b',1.5,3) IN (row(3,NULL,3), row('a',1.5,3), row(1,3,3));
17
select row('b',1.5,3) IN (row('b',NULL,3), row('a',1.5,3), row(1,3,3));
18
select row('b',1.5,3) IN (row('b',NULL,4), row('a',1.5,3), row(1,3,3));
19
select (1,2,(3,4)) IN ((3,2,(3,4)), (1,2,(3,4)));
21
select row(1,2,row(3,4)) IN (row(3,2,row(3,4)), row(1,2,4));
22
select row(1,2,row(3,4)) IN (row(3,2,row(3,4)), row(1,2,row(3,NULL)));
23
explain extended select row(1,2,row(3,4)) IN (row(3,2,row(3,4)), row(1,2,row(3,NULL)));
25
SELECT (1,2,3)=(0,NULL,3);
26
SELECT (1,2,3)=(1,NULL,3);
27
# here's something for Sanja to fix :)
28
SELECT (1,2,3)=(1,NULL,0);
30
SELECT ROW(1,2,3)=ROW(1,2,3);
31
SELECT ROW(2,2,3)=ROW(1+1,2,3);
32
SELECT ROW(1,2,3)=ROW(1+1,2,3);
33
SELECT ROW(1,2,3)<ROW(1+1,2,3);
34
SELECT ROW(1,2,3)>ROW(1+1,2,3);
35
SELECT ROW(1,2,3)<=ROW(1+1,2,3);
36
SELECT ROW(1,2,3)>=ROW(1+1,2,3);
37
SELECT ROW(1,2,3)<>ROW(1+1,2,3);
38
SELECT ROW(NULL,2,3)=ROW(NULL,2,3);
39
SELECT ROW(NULL,2,3)<=>ROW(NULL,2,3);
40
SELECT ROW(1,2,ROW(3,4,5))=ROW(1,2,ROW(3,4,5));
41
SELECT ROW('test',2,3.33)=ROW('test',2,3.33);
43
SELECT ROW('test',2,3.33)=ROW('test',2,3.33,4);
44
SELECT ROW('test',2,ROW(3,33))=ROW('test',2,ROW(3,33));
45
SELECT ROW('test',2,ROW(3,33))=ROW('test',2,ROW(3,3));
46
SELECT ROW('test',2,ROW(3,33))=ROW('test',2,ROW(3,NULL));
48
SELECT ROW('test',2,ROW(3,33))=ROW('test',2,4);
50
create table t1 ( a int, b int, c int);
51
insert into t1 values (1,2,3), (2,3,1), (3,2,1), (1,2,NULL);
52
select * from t1 where ROW(1,2,3)=ROW(a,b,c);
53
select * from t1 where ROW(0,2,3)=ROW(a,b,c);
54
select * from t1 where ROW(1,2,3)<ROW(a,b,c);
55
select ROW(a,2,3) IN(row(1,b,c), row(2,3,1)) from t1;
56
select ROW(c,2,3) IN(row(1,b,a), row(2,3,1)) from t1;
57
select ROW(a,b,c) IN(row(1,2,3), row(3,2,1)) from t1;
58
select ROW(1,2,3) IN(row(a,b,c), row(1,2,3)) from t1;
64
create table t1 (i int);
66
select 1 from t1 where ROW(1,1);
68
select count(*) from t1 order by ROW(1,1);
70
select count(*) from t1 having (1,1) order by i;
73
create table t1 (a int, b int);
74
insert into t1 values (1, 4);
75
insert into t1 values (10, 40);
76
insert into t1 values (1, 4);
77
insert into t1 values (10, 43);
78
insert into t1 values (1, 4);
79
insert into t1 values (10, 41);
80
insert into t1 values (1, 4);
81
insert into t1 values (10, 43);
82
insert into t1 values (1, 4);
83
select a, MAX(b), (1, MAX(b)) = (1, 4) from t1 group by a;
85
SELECT ROW(2,10) <=> ROW(3,4);
86
SELECT ROW(NULL,10) <=> ROW(3,NULL);
91
# Correct NULL handling in row comporison (BUG#12509)
93
SELECT ROW(1,1,1) = ROW(1,1,1) as `1`, ROW(1,1,1) = ROW(1,2,1) as `0`, ROW(1,NULL,1) = ROW(2,2,1) as `0`, ROW(1,NULL,1) = ROW(1,2,2) as `0`, ROW(1,NULL,1) = ROW(1,2,1) as `null` ;
94
select row(NULL,1)=(2,0);