772
730
int node = current->crosses(this, *i);
775
735
// Determine whether it's save to continue or not.
776
736
// If we have a crossing route, there are two possibilities:
777
737
// 1) This is an interestion
778
738
// 2) This is oncoming two-way traffic, using the same taxiway.
779
739
//cerr << "Hold check 1 : " << id << " has common node " << node << endl;
790
744
if (current->isOpposing(this, *i, node))