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/* Expression parsing for plural form selection.
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Copyright (C) 2000, 2001 Free Software Foundation, Inc.
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Written by Ulrich Drepper <drepper@cygnus.com>, 2000.
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This program is free software; you can redistribute it and/or modify it
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under the terms of the GNU Library General Public License as published
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by the Free Software Foundation; either version 2, or (at your option)
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This program is distributed in the hope that it will be useful,
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but WITHOUT ANY WARRANTY; without even the implied warranty of
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MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
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Library General Public License for more details.
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You should have received a copy of the GNU Library General Public
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License along with this program; if not, write to the Free Software
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Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307,
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/* The bison generated parser uses alloca. AIX 3 forces us to put this
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declaration at the beginning of the file. The declaration in bison's
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skeleton file comes too late. This must come before <config.h>
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because <config.h> may include arbitrary system headers. */
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#if defined _AIX && !defined __GNUC__
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#include "plural-exp.h"
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/* The main function generated by the parser is called __gettextparse,
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but we want it to be called PLURAL_PARSE. */
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# define __gettextparse PLURAL_PARSE
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#define YYLEX_PARAM &((struct parse_args *) arg)->cp
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#define YYPARSE_PARAM arg
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unsigned long int num;
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struct expression *exp;
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/* Prototypes for local functions. */
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static struct expression *new_exp PARAMS ((int nargs, enum operator op,
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struct expression * const *args));
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static inline struct expression *new_exp_0 PARAMS ((enum operator op));
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static inline struct expression *new_exp_1 PARAMS ((enum operator op,
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struct expression *right));
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static struct expression *new_exp_2 PARAMS ((enum operator op,
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struct expression *left,
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struct expression *right));
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static inline struct expression *new_exp_3 PARAMS ((enum operator op,
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struct expression *bexp,
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struct expression *tbranch,
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struct expression *fbranch));
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static int yylex PARAMS ((YYSTYPE *lval, const char **pexp));
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static void yyerror PARAMS ((const char *str));
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/* Allocation of expressions. */
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static struct expression *
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new_exp (nargs, op, args)
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struct expression * const *args;
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struct expression *newp;
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/* If any of the argument could not be malloc'ed, just return NULL. */
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for (i = nargs - 1; i >= 0; i--)
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/* Allocate a new expression. */
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newp = (struct expression *) malloc (sizeof (*newp));
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for (i = nargs - 1; i >= 0; i--)
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newp->val.args[i] = args[i];
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for (i = nargs - 1; i >= 0; i--)
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FREE_EXPRESSION (args[i]);
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static inline struct expression *
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return new_exp (0, op, NULL);
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static inline struct expression *
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new_exp_1 (op, right)
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struct expression *right;
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struct expression *args[1];
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return new_exp (1, op, args);
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static struct expression *
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new_exp_2 (op, left, right)
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struct expression *left;
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struct expression *right;
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struct expression *args[2];
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return new_exp (2, op, args);
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static inline struct expression *
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new_exp_3 (op, bexp, tbranch, fbranch)
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struct expression *bexp;
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struct expression *tbranch;
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struct expression *fbranch;
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struct expression *args[3];
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return new_exp (3, op, args);
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/* This declares that all operators have the same associativity and the
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precedence order as in C. See [Harbison, Steele: C, A Reference Manual].
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There is no unary minus and no bitwise operators.
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Operators with the same syntactic behaviour have been merged into a single
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token, to save space in the array generated by bison. */
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%left EQUOP2 /* == != */
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%left CMPOP2 /* < > <= >= */
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%left ADDOP2 /* + - */
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%left MULOP2 /* * / % */
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%token <op> EQUOP2 CMPOP2 ADDOP2 MULOP2
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((struct parse_args *) arg)->res = $1;
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exp: exp '?' exp ':' exp
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$$ = new_exp_3 (qmop, $1, $3, $5);
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$$ = new_exp_2 (lor, $1, $3);
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$$ = new_exp_2 (land, $1, $3);
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$$ = new_exp_2 ($2, $1, $3);
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$$ = new_exp_2 ($2, $1, $3);
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$$ = new_exp_2 ($2, $1, $3);
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$$ = new_exp_2 ($2, $1, $3);
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$$ = new_exp_1 (lnot, $2);
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$$ = new_exp_0 (var);
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if (($$ = new_exp_0 (num)) != NULL)
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FREE_EXPRESSION (exp)
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struct expression *exp;
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/* Handle the recursive case. */
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FREE_EXPRESSION (exp->val.args[2]);
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FREE_EXPRESSION (exp->val.args[1]);
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FREE_EXPRESSION (exp->val.args[0]);
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const char *exp = *pexp;
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if (exp[0] != ' ' && exp[0] != '\t')
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case '0': case '1': case '2': case '3': case '4':
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case '5': case '6': case '7': case '8': case '9':
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unsigned long int n = result - '0';
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while (exp[0] >= '0' && exp[0] <= '9')
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lval->op = not_equal;
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if (exp[0] == result)
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lval->op = less_or_equal;
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lval->op = less_than;
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lval->op = greater_or_equal;
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lval->op = greater_than;
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/* Nothing, just return the character. */
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/* Be safe and let the user call this function again. */
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/* Do nothing. We don't print error messages here. */