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<div class="section" id="floating-point-arithmetic-issues-and-limitations">
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<span id="tut-fp-issues"></span><h1>15. Floating Point Arithmetic: Issues and Limitations<a class="headerlink" href="#floating-point-arithmetic-issues-and-limitations" title="Permalink to this headline">¶</a></h1>
78
<p>Floating-point numbers are represented in computer hardware as base 2 (binary)
79
fractions. For example, the decimal fraction</p>
80
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.125</span>
83
<p>has value 1/10 + 2/100 + 5/1000, and in the same way the binary fraction</p>
84
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.001</span>
87
<p>has value 0/2 + 0/4 + 1/8. These two fractions have identical values, the only
88
real difference being that the first is written in base 10 fractional notation,
89
and the second in base 2.</p>
90
<p>Unfortunately, most decimal fractions cannot be represented exactly as binary
91
fractions. A consequence is that, in general, the decimal floating-point
92
numbers you enter are only approximated by the binary floating-point numbers
93
actually stored in the machine.</p>
94
<p>The problem is easier to understand at first in base 10. Consider the fraction
95
1/3. You can approximate that as a base 10 fraction:</p>
96
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.3</span>
100
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.33</span>
104
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.333</span>
107
<p>and so on. No matter how many digits you’re willing to write down, the result
108
will never be exactly 1/3, but will be an increasingly better approximation of
110
<p>In the same way, no matter how many base 2 digits you’re willing to use, the
111
decimal value 0.1 cannot be represented exactly as a base 2 fraction. In base
112
2, 1/10 is the infinitely repeating fraction</p>
113
<div class="highlight-python3"><div class="highlight"><pre><span class="mf">0.0001100110011001100110011001100110011001100110011</span><span class="o">...</span>
116
<p>Stop at any finite number of bits, and you get an approximation. On most
117
machines today, floats are approximated using a binary fraction with
118
the numerator using the first 53 bits starting with the most significant bit and
119
with the denominator as a power of two. In the case of 1/10, the binary fraction
120
is <code class="docutils literal"><span class="pre">3602879701896397</span> <span class="pre">/</span> <span class="pre">2</span> <span class="pre">**</span> <span class="pre">55</span></code> which is close to but not exactly
121
equal to the true value of 1/10.</p>
122
<p>Many users are not aware of the approximation because of the way values are
123
displayed. Python only prints a decimal approximation to the true decimal
124
value of the binary approximation stored by the machine. On most machines, if
125
Python were to print the true decimal value of the binary approximation stored
126
for 0.1, it would have to display</p>
127
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="mf">0.1</span>
128
<span class="go">0.1000000000000000055511151231257827021181583404541015625</span>
131
<p>That is more digits than most people find useful, so Python keeps the number
132
of digits manageable by displaying a rounded value instead</p>
133
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="mi">1</span> <span class="o">/</span> <span class="mi">10</span>
134
<span class="go">0.1</span>
137
<p>Just remember, even though the printed result looks like the exact value
138
of 1/10, the actual stored value is the nearest representable binary fraction.</p>
139
<p>Interestingly, there are many different decimal numbers that share the same
140
nearest approximate binary fraction. For example, the numbers <code class="docutils literal"><span class="pre">0.1</span></code> and
141
<code class="docutils literal"><span class="pre">0.10000000000000001</span></code> and
142
<code class="docutils literal"><span class="pre">0.1000000000000000055511151231257827021181583404541015625</span></code> are all
143
approximated by <code class="docutils literal"><span class="pre">3602879701896397</span> <span class="pre">/</span> <span class="pre">2</span> <span class="pre">**</span> <span class="pre">55</span></code>. Since all of these decimal
144
values share the same approximation, any one of them could be displayed
145
while still preserving the invariant <code class="docutils literal"><span class="pre">eval(repr(x))</span> <span class="pre">==</span> <span class="pre">x</span></code>.</p>
146
<p>Historically, the Python prompt and built-in <a class="reference internal" href="../library/functions.html#repr" title="repr"><code class="xref py py-func docutils literal"><span class="pre">repr()</span></code></a> function would choose
147
the one with 17 significant digits, <code class="docutils literal"><span class="pre">0.10000000000000001</span></code>. Starting with
148
Python 3.1, Python (on most systems) is now able to choose the shortest of
149
these and simply display <code class="docutils literal"><span class="pre">0.1</span></code>.</p>
150
<p>Note that this is in the very nature of binary floating-point: this is not a bug
151
in Python, and it is not a bug in your code either. You’ll see the same kind of
152
thing in all languages that support your hardware’s floating-point arithmetic
153
(although some languages may not <em>display</em> the difference by default, or in all
155
<p>For more pleasant output, you may wish to use string formatting to produce a limited number of significant digits:</p>
156
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="nb">format</span><span class="p">(</span><span class="n">math</span><span class="o">.</span><span class="n">pi</span><span class="p">,</span> <span class="s1">'.12g'</span><span class="p">)</span> <span class="c1"># give 12 significant digits</span>
157
<span class="go">'3.14159265359'</span>
159
<span class="gp">>>> </span><span class="nb">format</span><span class="p">(</span><span class="n">math</span><span class="o">.</span><span class="n">pi</span><span class="p">,</span> <span class="s1">'.2f'</span><span class="p">)</span> <span class="c1"># give 2 digits after the point</span>
160
<span class="go">'3.14'</span>
162
<span class="gp">>>> </span><span class="nb">repr</span><span class="p">(</span><span class="n">math</span><span class="o">.</span><span class="n">pi</span><span class="p">)</span>
163
<span class="go">'3.141592653589793'</span>
166
<p>It’s important to realize that this is, in a real sense, an illusion: you’re
167
simply rounding the <em>display</em> of the true machine value.</p>
168
<p>One illusion may beget another. For example, since 0.1 is not exactly 1/10,
169
summing three values of 0.1 may not yield exactly 0.3, either:</p>
170
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="o">.</span><span class="mi">1</span> <span class="o">+</span> <span class="o">.</span><span class="mi">1</span> <span class="o">+</span> <span class="o">.</span><span class="mi">1</span> <span class="o">==</span> <span class="o">.</span><span class="mi">3</span>
171
<span class="go">False</span>
174
<p>Also, since the 0.1 cannot get any closer to the exact value of 1/10 and
175
0.3 cannot get any closer to the exact value of 3/10, then pre-rounding with
176
<a class="reference internal" href="../library/functions.html#round" title="round"><code class="xref py py-func docutils literal"><span class="pre">round()</span></code></a> function cannot help:</p>
177
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">1</span><span class="p">,</span> <span class="mi">1</span><span class="p">)</span> <span class="o">+</span> <span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">1</span><span class="p">,</span> <span class="mi">1</span><span class="p">)</span> <span class="o">+</span> <span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">1</span><span class="p">,</span> <span class="mi">1</span><span class="p">)</span> <span class="o">==</span> <span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">3</span><span class="p">,</span> <span class="mi">1</span><span class="p">)</span>
178
<span class="go">False</span>
181
<p>Though the numbers cannot be made closer to their intended exact values,
182
the <a class="reference internal" href="../library/functions.html#round" title="round"><code class="xref py py-func docutils literal"><span class="pre">round()</span></code></a> function can be useful for post-rounding so that results
183
with inexact values become comparable to one another:</p>
184
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">1</span> <span class="o">+</span> <span class="o">.</span><span class="mi">1</span> <span class="o">+</span> <span class="o">.</span><span class="mi">1</span><span class="p">,</span> <span class="mi">10</span><span class="p">)</span> <span class="o">==</span> <span class="nb">round</span><span class="p">(</span><span class="o">.</span><span class="mi">3</span><span class="p">,</span> <span class="mi">10</span><span class="p">)</span>
185
<span class="go">True</span>
188
<p>Binary floating-point arithmetic holds many surprises like this. The problem
189
with “0.1” is explained in precise detail below, in the “Representation Error”
190
section. See <a class="reference external" href="http://www.lahey.com/float.htm">The Perils of Floating Point</a>
191
for a more complete account of other common surprises.</p>
192
<p>As that says near the end, “there are no easy answers.” Still, don’t be unduly
193
wary of floating-point! The errors in Python float operations are inherited
194
from the floating-point hardware, and on most machines are on the order of no
195
more than 1 part in 2**53 per operation. That’s more than adequate for most
196
tasks, but you do need to keep in mind that it’s not decimal arithmetic and
197
that every float operation can suffer a new rounding error.</p>
198
<p>While pathological cases do exist, for most casual use of floating-point
199
arithmetic you’ll see the result you expect in the end if you simply round the
200
display of your final results to the number of decimal digits you expect.
201
<a class="reference internal" href="../library/stdtypes.html#str" title="str"><code class="xref py py-func docutils literal"><span class="pre">str()</span></code></a> usually suffices, and for finer control see the <a class="reference internal" href="../library/stdtypes.html#str.format" title="str.format"><code class="xref py py-meth docutils literal"><span class="pre">str.format()</span></code></a>
202
method’s format specifiers in <a class="reference internal" href="../library/string.html#formatstrings"><span>Format String Syntax</span></a>.</p>
203
<p>For use cases which require exact decimal representation, try using the
204
<a class="reference internal" href="../library/decimal.html#module-decimal" title="decimal: Implementation of the General Decimal Arithmetic Specification."><code class="xref py py-mod docutils literal"><span class="pre">decimal</span></code></a> module which implements decimal arithmetic suitable for
205
accounting applications and high-precision applications.</p>
206
<p>Another form of exact arithmetic is supported by the <a class="reference internal" href="../library/fractions.html#module-fractions" title="fractions: Rational numbers."><code class="xref py py-mod docutils literal"><span class="pre">fractions</span></code></a> module
207
which implements arithmetic based on rational numbers (so the numbers like
208
1/3 can be represented exactly).</p>
209
<p>If you are a heavy user of floating point operations you should take a look
210
at the Numerical Python package and many other packages for mathematical and
211
statistical operations supplied by the SciPy project. See <<a class="reference external" href="http://scipy.org">http://scipy.org</a>>.</p>
212
<p>Python provides tools that may help on those rare occasions when you really
213
<em>do</em> want to know the exact value of a float. The
214
<a class="reference internal" href="../library/stdtypes.html#float.as_integer_ratio" title="float.as_integer_ratio"><code class="xref py py-meth docutils literal"><span class="pre">float.as_integer_ratio()</span></code></a> method expresses the value of a float as a
216
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">x</span> <span class="o">=</span> <span class="mf">3.14159</span>
217
<span class="gp">>>> </span><span class="n">x</span><span class="o">.</span><span class="n">as_integer_ratio</span><span class="p">()</span>
218
<span class="go">(3537115888337719, 1125899906842624)</span>
221
<p>Since the ratio is exact, it can be used to losslessly recreate the
223
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">x</span> <span class="o">==</span> <span class="mi">3537115888337719</span> <span class="o">/</span> <span class="mi">1125899906842624</span>
224
<span class="go">True</span>
227
<p>The <a class="reference internal" href="../library/stdtypes.html#float.hex" title="float.hex"><code class="xref py py-meth docutils literal"><span class="pre">float.hex()</span></code></a> method expresses a float in hexadecimal (base
228
16), again giving the exact value stored by your computer:</p>
229
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">x</span><span class="o">.</span><span class="n">hex</span><span class="p">()</span>
230
<span class="go">'0x1.921f9f01b866ep+1'</span>
233
<p>This precise hexadecimal representation can be used to reconstruct
234
the float value exactly:</p>
235
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">x</span> <span class="o">==</span> <span class="nb">float</span><span class="o">.</span><span class="n">fromhex</span><span class="p">(</span><span class="s1">'0x1.921f9f01b866ep+1'</span><span class="p">)</span>
236
<span class="go">True</span>
239
<p>Since the representation is exact, it is useful for reliably porting values
240
across different versions of Python (platform independence) and exchanging
241
data with other languages that support the same format (such as Java and C99).</p>
242
<p>Another helpful tool is the <a class="reference internal" href="../library/math.html#math.fsum" title="math.fsum"><code class="xref py py-func docutils literal"><span class="pre">math.fsum()</span></code></a> function which helps mitigate
243
loss-of-precision during summation. It tracks “lost digits” as values are
244
added onto a running total. That can make a difference in overall accuracy
245
so that the errors do not accumulate to the point where they affect the
247
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="nb">sum</span><span class="p">([</span><span class="mf">0.1</span><span class="p">]</span> <span class="o">*</span> <span class="mi">10</span><span class="p">)</span> <span class="o">==</span> <span class="mf">1.0</span>
248
<span class="go">False</span>
249
<span class="gp">>>> </span><span class="n">math</span><span class="o">.</span><span class="n">fsum</span><span class="p">([</span><span class="mf">0.1</span><span class="p">]</span> <span class="o">*</span> <span class="mi">10</span><span class="p">)</span> <span class="o">==</span> <span class="mf">1.0</span>
250
<span class="go">True</span>
253
<div class="section" id="representation-error">
254
<span id="tut-fp-error"></span><h2>15.1. Representation Error<a class="headerlink" href="#representation-error" title="Permalink to this headline">¶</a></h2>
255
<p>This section explains the “0.1” example in detail, and shows how you can perform
256
an exact analysis of cases like this yourself. Basic familiarity with binary
257
floating-point representation is assumed.</p>
258
<p><em class="dfn">Representation error</em> refers to the fact that some (most, actually)
259
decimal fractions cannot be represented exactly as binary (base 2) fractions.
260
This is the chief reason why Python (or Perl, C, C++, Java, Fortran, and many
261
others) often won’t display the exact decimal number you expect.</p>
262
<p>Why is that? 1/10 is not exactly representable as a binary fraction. Almost all
263
machines today (November 2000) use IEEE-754 floating point arithmetic, and
264
almost all platforms map Python floats to IEEE-754 “double precision”. 754
265
doubles contain 53 bits of precision, so on input the computer strives to
266
convert 0.1 to the closest fraction it can of the form <em>J</em>/2**<em>N</em> where <em>J</em> is
267
an integer containing exactly 53 bits. Rewriting</p>
268
<div class="highlight-python3"><div class="highlight"><pre><span class="mi">1</span> <span class="o">/</span> <span class="mi">10</span> <span class="o">~=</span> <span class="n">J</span> <span class="o">/</span> <span class="p">(</span><span class="mi">2</span><span class="o">**</span><span class="n">N</span><span class="p">)</span>
272
<div class="highlight-python3"><div class="highlight"><pre><span class="n">J</span> <span class="o">~=</span> <span class="mi">2</span><span class="o">**</span><span class="n">N</span> <span class="o">/</span> <span class="mi">10</span>
275
<p>and recalling that <em>J</em> has exactly 53 bits (is <code class="docutils literal"><span class="pre">>=</span> <span class="pre">2**52</span></code> but <code class="docutils literal"><span class="pre"><</span> <span class="pre">2**53</span></code>),
276
the best value for <em>N</em> is 56:</p>
277
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="mi">2</span><span class="o">**</span><span class="mi">52</span> <span class="o"><=</span> <span class="mi">2</span><span class="o">**</span><span class="mi">56</span> <span class="o">//</span> <span class="mi">10</span> <span class="o"><</span> <span class="mi">2</span><span class="o">**</span><span class="mi">53</span>
278
<span class="go">True</span>
281
<p>That is, 56 is the only value for <em>N</em> that leaves <em>J</em> with exactly 53 bits. The
282
best possible value for <em>J</em> is then that quotient rounded:</p>
283
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">q</span><span class="p">,</span> <span class="n">r</span> <span class="o">=</span> <span class="nb">divmod</span><span class="p">(</span><span class="mi">2</span><span class="o">**</span><span class="mi">56</span><span class="p">,</span> <span class="mi">10</span><span class="p">)</span>
284
<span class="gp">>>> </span><span class="n">r</span>
285
<span class="go">6</span>
288
<p>Since the remainder is more than half of 10, the best approximation is obtained
290
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="n">q</span><span class="o">+</span><span class="mi">1</span>
291
<span class="go">7205759403792794</span>
294
<p>Therefore the best possible approximation to 1/10 in 754 double precision is:</p>
295
<div class="highlight-python3"><div class="highlight"><pre><span class="mi">7205759403792794</span> <span class="o">/</span> <span class="mi">2</span> <span class="o">**</span> <span class="mi">56</span>
298
<p>Dividing both the numerator and denominator by two reduces the fraction to:</p>
299
<div class="highlight-python3"><div class="highlight"><pre><span class="mi">3602879701896397</span> <span class="o">/</span> <span class="mi">2</span> <span class="o">**</span> <span class="mi">55</span>
302
<p>Note that since we rounded up, this is actually a little bit larger than 1/10;
303
if we had not rounded up, the quotient would have been a little bit smaller than
304
1/10. But in no case can it be <em>exactly</em> 1/10!</p>
305
<p>So the computer never “sees” 1/10: what it sees is the exact fraction given
306
above, the best 754 double approximation it can get:</p>
307
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="mf">0.1</span> <span class="o">*</span> <span class="mi">2</span> <span class="o">**</span> <span class="mi">55</span>
308
<span class="go">3602879701896397.0</span>
311
<p>If we multiply that fraction by 10**55, we can see the value out to
312
55 decimal digits:</p>
313
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="mi">3602879701896397</span> <span class="o">*</span> <span class="mi">10</span> <span class="o">**</span> <span class="mi">55</span> <span class="o">//</span> <span class="mi">2</span> <span class="o">**</span> <span class="mi">55</span>
314
<span class="go">1000000000000000055511151231257827021181583404541015625</span>
317
<p>meaning that the exact number stored in the computer is equal to
318
the decimal value 0.1000000000000000055511151231257827021181583404541015625.
319
Instead of displaying the full decimal value, many languages (including
320
older versions of Python), round the result to 17 significant digits:</p>
321
<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="nb">format</span><span class="p">(</span><span class="mf">0.1</span><span class="p">,</span> <span class="s1">'.17f'</span><span class="p">)</span>
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<span class="go">'0.10000000000000001'</span>
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<p>The <a class="reference internal" href="../library/fractions.html#module-fractions" title="fractions: Rational numbers."><code class="xref py py-mod docutils literal"><span class="pre">fractions</span></code></a> and <a class="reference internal" href="../library/decimal.html#module-decimal" title="decimal: Implementation of the General Decimal Arithmetic Specification."><code class="xref py py-mod docutils literal"><span class="pre">decimal</span></code></a> modules make these calculations
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<div class="highlight-python3"><div class="highlight"><pre><span class="gp">>>> </span><span class="kn">from</span> <span class="nn">decimal</span> <span class="k">import</span> <span class="n">Decimal</span>
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<span class="gp">>>> </span><span class="kn">from</span> <span class="nn">fractions</span> <span class="k">import</span> <span class="n">Fraction</span>
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<span class="gp">>>> </span><span class="n">Fraction</span><span class="o">.</span><span class="n">from_float</span><span class="p">(</span><span class="mf">0.1</span><span class="p">)</span>
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<span class="go">Fraction(3602879701896397, 36028797018963968)</span>
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<span class="gp">>>> </span><span class="p">(</span><span class="mf">0.1</span><span class="p">)</span><span class="o">.</span><span class="n">as_integer_ratio</span><span class="p">()</span>
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<span class="go">(3602879701896397, 36028797018963968)</span>
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<span class="gp">>>> </span><span class="n">Decimal</span><span class="o">.</span><span class="n">from_float</span><span class="p">(</span><span class="mf">0.1</span><span class="p">)</span>
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<span class="go">Decimal('0.1000000000000000055511151231257827021181583404541015625')</span>
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<span class="gp">>>> </span><span class="nb">format</span><span class="p">(</span><span class="n">Decimal</span><span class="o">.</span><span class="n">from_float</span><span class="p">(</span><span class="mf">0.1</span><span class="p">),</span> <span class="s1">'.17'</span><span class="p">)</span>
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<span class="go">'0.10000000000000001'</span>
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<li><a class="reference internal" href="#">15. Floating Point Arithmetic: Issues and Limitations</a><ul>
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