1
; This test makes sure that these instructions are properly eliminated.
4
; RUN: opt < %s -instcombine -S | FileCheck %s
7
define i32 @test1(i32 %A) {
8
%B = xor i32 %A, -1 ; <i32> [#uses=1]
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%C = xor i32 %B, -1 ; <i32> [#uses=1]
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define i1 @test2(i32 %A, i32 %B) {
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; Can change into setge
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%cond = icmp sle i32 %A, %B ; <i1> [#uses=1]
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%Ret = xor i1 %cond, true ; <i1> [#uses=1]
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; Test that demorgans law can be instcombined
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define i32 @test3(i32 %A, i32 %B) {
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%a = xor i32 %A, -1 ; <i32> [#uses=1]
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%b = xor i32 %B, -1 ; <i32> [#uses=1]
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%c = and i32 %a, %b ; <i32> [#uses=1]
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%d = xor i32 %c, -1 ; <i32> [#uses=1]
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; Test that demorgens law can work with constants
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define i32 @test4(i32 %A, i32 %B) {
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%a = xor i32 %A, -1 ; <i32> [#uses=1]
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%c = and i32 %a, 5 ; <i32> [#uses=1]
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%d = xor i32 %c, -1 ; <i32> [#uses=1]
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; test the mirror of demorgans law...
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define i32 @test5(i32 %A, i32 %B) {
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%a = xor i32 %A, -1 ; <i32> [#uses=1]
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%b = xor i32 %B, -1 ; <i32> [#uses=1]
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%c = or i32 %a, %b ; <i32> [#uses=1]
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%d = xor i32 %c, -1 ; <i32> [#uses=1]
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define zeroext i8 @test6(i32 %a, i32 %b) nounwind {
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%tmp1not = xor i32 %a, -1 ; <i32> [#uses=1]
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%tmp2not = xor i32 %b, -1 ; <i32> [#uses=1]
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%tmp3 = icmp slt i32 %tmp1not, %tmp2not ; <i1> [#uses=1]
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%retval67 = zext i1 %tmp3 to i8 ; <i8> [#uses=1]
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define <2 x i1> @test7(<2 x i32> %A, <2 x i32> %B) {
57
%cond = icmp sle <2 x i32> %A, %B
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%Ret = xor <2 x i1> %cond, <i1 true, i1 true>